Question: I wrote the value of probability p as 1 / 3 , so , the value should be 0 . 3 3 3 . .

I wrote the value of probability p as 1/3, so, the value should be 0.333... You wrote it as 0.13. it is a mistake isnt it? Please revise the result again. Additionally, I tried to calculate the probability of occurrence of the U-turn with loss events.
I calculated both of the case having the 25 and 45 samples.
P[x=k]=([n
k])pk(1-p)n-k
for k=0,1,2,dots,n
([n
k])=?nCk=n!k!(n-k)!
When n=25,k=22, and p=13
P[x]=25!**(13)22**(23)322!32.17**10-8
Also, when n=45,k=32, and p=13
P[x]=45!**(13)32**(23)133!132.02**10?-7
Furthermore, in case of determining the probability of "rarity" through simulation,
I repeated 1000 trials of occurring the U-turn with loss events 45 times, and I collected data on the number of the
events by using RStudio Desktop.
> coin-rbinom(1000,45,0.33
> coin-rbinom(1000,45,0.33)
>m- mean(coin)
>s-sd( coin )
>c(m,s)
[1]14.760000,3.094184
>cs32-(32-m)???2s???2
>cs32
[1]31.04433
> chisqcoin -( coin-m)???2s???2
> hist(chisqcoin,col="skyblue")
> abline(v=cs32,col= red")
> length(chisqcoin[chisqcoin cs32)?1000
 I wrote the value of probability p as 1/3, so, the

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