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i(1) 4. A system is described by the differential equation (1) + 450(1) + 50000v() = 500001(), where v(l) is the system output voltage and

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i(1) 4. A system is described by the differential equation (1) + 450(1) + 50000v() = 500001(), where v(l) is the system output voltage and i(t) = sin(1004) is the system input current. Note all that (1) Po(1) du(1) dl Use MATLAB to create a time vector from 0 to 0.3 seconds with a time step of 0.0001. Obtain v(), which is the solution to the differential equation, by using the MATLAB lsin command. Then, plot the system input current using a dashed black line and the system output voltage using a solid black line on the same graph in the interval 0

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