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ID: 198.123.5.198 DHCP IP: 192.168.1.8 All switches are learning switch. Server ARP tables and switch tables are initially empty. Router 2 has NAT, Router 1
ID: 198.123.5.198 DHCP IP: 192.168.1.8 All switches are learning switch. Server ARP tables and switch tables are initially empty. Router 2 has NAT, Router 1 does not have. LAN IP: WAN IP: Q4. Answer the following questions: Server A 192.168.1.1 198.123.6.183 Wall-A a. How many subnets are there in the figure? b. Using only the information given in the figure, what would be the minimum subnet mask value Switch 1 Router 1 Router 2 for the subnet of Laptop B? (Router + NAT + Wireless AP in a single box) c. Describe whether 198.125.5.163 is a legal IP Wall-B address for Laptop B if the subnet mask is 26. Switch 2 IP: 192.168.1.9 d. Suppose that Laptop B is newly attached to Laptop B Laptop A the network. Describe how it obtains an IP address dynamically. Q3. Suppose that Wall-A wants to establish a TCP connection with e. Will Laptop B need IP address of Router 1? If Server A and sends a TCP SYN segment. Answer the following: no why? If yes why it needs and how it obtains a. What are the actions taken in Router 2 (NAT)? this address? b. Which device would need MAC address of Server A? How does it obtain f. Suppose that Wall-A and Wall-B uses Carrier 2. this address? Sense Multiple Access (CSMA) while sending a c. Now, Server A sends back a TCP SYNACK segment. What would be the frame to Router 2. Is it possible to have actions taken in Router 2 (NAT)? collisions? Why? What would be an advantage of d. What would be the contents of switch tables in Switch 1 and Switch 2 using CSMA instead of a channel partitioning Four microphone is not algorithm such as FDMA or TDMA? Please check your connection or use wants to establish a connection with a g. Lets say that CRC is used for error detection. If different mic.ocess running in Wall-B. What is the problem? Describe a data is 101110011 and Generator (G) is 1001, solution with the aid of Server A. calculate the CRC bits. he is not working.ication
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