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If 365 mL of 0.285 M MgCl is added to 125 mL of 0.215 M (NH)PO, how many moles of Mg(PO) precipitate will be formed?
If 365 mL of 0.285 M MgCl is added to 125 mL of 0.215 M (NH)PO, how many moles of Mg(PO) precipitate will be formed? The balanced equation is 3 MgCl(aq) + 2 (NH)PO(aq) Mg(PO)(s) + 6 NHCl((aq)
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