If $40\mathrm{.}5$ g of MgCl$$ are dissolved $500\mathrm{.}0$ g of water at $20\mathrm{.}0\backslash$deg C in an insulated container, a temperature change is observed. The $$H of solution of MgCl$$ is $-160\mathrm{.}0$ kJ$/$mol$.$ Assuming that the specific heat of the solution is $4\mathrm{.}184$ J$/($g $\backslash$deg C$),$ and that no heat is gained or lost by the container, what will be the final temperature of the solution? plz answer it correctly,