If 40.0 grams of methane (CH₄) react with 16.3 grams of water (H₂O), how many grams of H₂ are produced and what is the limiting reactant?

CH₄ + 2H₂O --> 4H₂ + CO₂

Fill in the blanks in the set-up below. 40.0 g (#3) (#1) mol CH4 (#2) mol H2 CH4 grams H2 (#4) CH4 (#5) mol CH4 (#6) mol H2 Answer to the problem above (Round your answer to THREE digits): (#7) grams of H2 16.3 g H2O (#8) mol H20 (#9) mol H2 (#10) grams H2 (#11) 8 H20 (#12) mol H2O (#13) mol H2 Answer to the problem above (Round your answer to THREE digits): (#14) grams of H2 Word Bank: 16.042 20.1 18.016 1 1 4 2.016 44.01 1 16.3 1 2 3 2.016 1 4 3.65