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If a body is rotating on x-y plane about an axis perpendicular to the plane of motion that passes through point O, the angular momentum
If a body is rotating on x-y plane about an axis perpendicular to the plane of motion that passes through point O, the angular momentum of the body (Ho) is given by Ho = - (ydm)(vo)x + (xdm)(vo)y + (r2dm), where x & y are distances of a differential element of the body with dm mass measured from O, (vo) x and (vo)y are the components of the velocity Vo in the x and y directions, respectively, and r is the radial distance of the differential element dm of the body measured from O. The last term in in the expression for Ho is called __________________. Group of answer choices the center of mass of the body the center of gravity of the body the moment of inertia of the body about point O the moment of inertia of the body about point G
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