If a body is rotating on x-y plane about an axis perpendicular to the plane of motion that passes through point O, the angular momentum of the body (Ho) is given by Ho = - (ydm)(vo)x + (xdm)(vo)y + (r2dm), where x & y are distances of a differential element of the body with dm mass measured from O, (vo) x and (vo)y are the components of the velocity Vo in the x and y directions, respectively, and r is the radial distance of the differential element dm of the body measured from O. What happens to the above equation (of Ho) if point O is a fixed point? Group of answer choices There will be no change in the equation The last term becomes zero or the equation becomes Ho = - (ydm)(vo)x + (xdm)(vo)y The first term becomes zero or the equation becomes Ho = (xdm)(vo)y + (r2dm) The first two terms becomes zero or the equation becomes Ho = (r2dm)