Question
If a matrix A has dimension nn and has n linearly independent eigenvectors, it is diagonalizable. This means there exists a matrix P such that
If a matrix A has dimension nn and has n linearly independent eigenvectors, it is diagonalizable. This means there exists a matrix P such that P 1AP = D, where D is a diagonal matrix, and the diagonal is made up of the eigenvalues of A. P is constructed by taking the eigenvectors of A and using them as the columns of P. Your task is to write a program (function) that does the following Finds the eigenvectors of an input matrix A Checks if the eigenvectors are linearly independent (think determinant) if they are not linearly depended, exit the program & display error Displays P, P 1 and D (if possible) Shows that P DP 1 = A Show that your program works with a 33 matrix A
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