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If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals
=minus
16t squared
t2plus
+vtplus
+s, where h is in feet. If the object is propelled from a height of
8 feet with an initial velocity of
96 feet per second, its height h is given by the equation hequals
=minus
16t squared
t2plus
+96
96tplus
+8
8.
After how many seconds is the height 148
148 feet?
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