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If f(x)=4x26x+3f(x)=4x2-6x+3, find f'(5)f(-5). Use this to find the equation of the tangent line to the parabola y=4x26x+3y=4x2-6x+3 at the point (5,133)(-5,133). The equation of
If f(x)=4x26x+3f(x)=4x2-6x+3, find f'(5)f(-5). Use this to find the equation of the tangent line to the parabola y=4x26x+3y=4x2-6x+3 at the point (5,133)(-5,133). The equation of this tangent line can be written in the form y=mx+by=mx+b where m is: and where b is:
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