If I mixed $4\mathrm{.}476$ pounds of Sulfuric Acid at a strength of $98\mathrm{.}6\%$ with $3\mathrm{.}245$ pounds of water, I will get $7\mathrm{.}721$ pounds of dilute acid with a strength of $57\mathrm{.}16\%$ Sulfuric Acid. How many BTU$$s will be released? How do I calculate that?

My best estimate is $118$ BTU$/$lb X $7\mathrm{.}721$lb $=911\mathrm{.}08$ BTU according to a Heat of Dilution table.

If I take $7\mathrm{.}721$ pounds of $57\mathrm{.}16\%$ Sulfuric Acid and mix this with $2\mathrm{.}34$ pounds of Aluminum Hydroxide Al$($OH$)3$ this will make $10\mathrm{.}06$ pounds of Aluminum Sulfate Solution at $51\mathrm{.}01\%$ Aluminum Sulfate. How many BTU$$s will be released? How do I calculate that? Thank You