If one number is chosen randomly from the integers 1 through 10, the probability of getting a number that is odd and prime, by the multiplication rule, is shown below. P(odd) . P(prime|odd) = 5 3 3 10 5 10 Computing the product P(prime) . P(odd|prime) gives the same result. P(prime) . P(odd|prime) = 4 3 3 10 4 What does this result imply, in general, about the probability of an event of the form "A and B"? Choose the correct answer below. O A. It implies that P(A and B) = P(B and A) for any A and B, because P(B|A) = P(A|B). O B. It implies that P(A and B) = P(B and A) because either event odd and prime could be labeled A and the other labeled B. O C. 'It implies that calculating P(A and B) using the multiplication rule is only valid if both products P(A) . P(BJA) and P(B) . P(A|B) are checked and give the same result. O D. It implies that P(A and B) = P(B and A) for any A and B, because "A and B" is the same as "B and A