If

P_(xe)

of a system were to be plotted (on the

x

-axis)\ against the derived ratio of

m_(Hpxe)

to

m_(Hp)

(on the

y

-axis),\ what would be the expected result?\ A) A line with a

y

-intercept at 0 , and a slope of

K_(eq)

\ B) A line with a

y

-intercept at 1 , and a slope of

K_(p)

\ C) A line with a

y

-intercept at 0 , and a slope of

K_(p)

\ D) A line with a

y

-intercept at 0 , and a slope of

(1)/(K_(p))

\ Answer: C The passage states that the following relationship is adhered to:

K_(p)=m_(Hpxc)(m_(Hp)*P_(xe))^(-1)

. This\ can be rearranged to give

(m_(Hpx))/(m_(Hp))=K_(p)*P_(xc)

. If thought of as the standard

y=mx+b

form\ of a straight line, the

y

-intercept

(b)

is 0 and the slope is

K_(p)

.

Once the amount of gas absorbed into the protein has been thus determined, a gas-solution equilibrium constant can be calculated as follows: Kp=mHpx(mHpPxe)1. In this relation, mHpXe and mHp are the molarities of xenon-bound hemeprotein and free hemeprotein, respectively, and Pxc is the partial pressure of Xe in the surrounding atmosphere. Standard Keq values can then be derived using the Henry's Law constants (3103M/atm) for the absorption of Xe in aqueous solutions to convert Pxe into mxc. From these Keq values, thermodynamic parameters for Xe absorption could be determined (Table 1). 1. If Pxe of a system were to be plotted (on the x-axis) against the derived ratio of mHpXe to mHp (on the y-axis), what would be the expected result? A) A line with a y-intercept at 0 , and a slope of Keq B) A line with a y-intercept at 1 , and a slope of Kp C) A line with a y-intercept at 0 , and a slope of Kp D) A line with a y-intercept at 0 , and a slope of 1/Kp 1. C The passage states that the following relationship is adhered to: Kp=mHpXe(mHpPXe)1. This can be rearranged to give mHpX/mHp=KpPXc. If thought of as the standard y=mx+b form of a straight line, the y-intercept (b) is 0 and the slope is Kp