If sigma M is equal to 3.6848, what is the 95% confidence interval equal to and what conclusion can you make?

Please use the following information to answer the question. A researcher decided to evaluate the effectiveness of having asynchronous materials for their course. A random sample of 64 students had the asynchronous materials course. The general population's exam score forms a normal distribution with mu equal to 80 and sigma equal to 15. The average score for the sample is M equal to 82. Does the sample provide enough evidence to conclude that the asynchronous course's average exam score is significantly different from the general population at the 5% significance level? If sigma M is equal to 3.6848, what is the 95% confidence interval equal to and what conclusion can you make