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If the base area of the pyramid is A and the (perpendicular) height is h, then its volume is V = Ah/3. We examine the
If the base area of the pyramid is A and the (perpendicular) height is h, then its volume is V = Ah/3. We examine the surface xyz = 2 in the 1st octant x, y, z > 0. If we choose an arbitrary point on the surface, then the tangent plane of the surface at that point limits the tetrahedron together with the coordinate planes. Show that the volume of this tetrahedron does not depend on the chosen point and calculate this volume.
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