-If the coefficient of static friction between tires and pavement is .65, calculate the minimum torque that must be applied to the 66-cm-diameter tire of a 950-kg automobile in order to "lay rubber" (make the wheels spin, slipping as the car accelerates). Assume each wheel supports an equal share of the weight. (5.0x102 Nm) -A grinding wheel is in the form of a uniform solid disk of radius 6.99 cm and mass 2.02 kg. It starts from rest and accelerates uniformly under the action of the constant torque of 0.594 N.m that the motor exerts on the wheel. (a) How long does the wheel take to reach its final operating speed of 1290 rev/min? (b) Through how many revolutions does it turn while accelerating? (1.12s, 12.1 rev) -The combination of an applied force and a constant frictional force produces a constant total torque of 35.6 Nom on a wheel rotating about a fixed axis. The applied force acts for 6.06 s. During this time the angular speed of the wheel increases from 0 to 9.7 rad/s. The applied force is then removed, and the wheel comes to rest in 59.2 s. (a) Find the moment of inertia of the wheel. (b) Find the magnitude of the frictional torque. (c) Find the total number of revolutions of the wheel (22.2 kg m?, 3.64 Nm, 50.4 rev)