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If the t score have 199 degrees of freedom and a cumulative probability equal to 0.945. Using the table of Critical values of Student's t

If the t score have 199 degrees of freedom and a cumulative probability equal to 0.945. Using the table of Critical values of Student's t distribution with n degrees of freedom we find the critical value which is equal to 1.605.

How do you get the 1.605 ?????

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