If y = (4x+1)(x+3), find the equation of the tangent line to the curve at Tangent line: == -2. Let f(x) 4x28x+11 = The slope of the tangent line to the graph of f(x) at the point (4,43) is The equation of the tangent line to the graph of f(x) at (4,43) is y = mx + b for m and b Hint: the slope is given by the derivative at = 4, ie. lim x +4 f(4+h) f(4) h If y = 2 sin(x), find the equation of the tangent line to the curve at x = = Tangent line: Given that f(8) = 1 and f'(8) = -4, find an equation for the tangent line to the graph of y = f(x) at x = 8. y =: If f(x)=2x+ f'(5) = 2 . Use this to find the equation of the tangent line to the curve y = 2;c + y = mx + b, where m is the slope and b is the y-intercept. 2 8 at the point (5, 10.4). Write your answer in the form: Let h(x) 3 3x3, h'(2) - Use this to find the equation of the tangent line to the curve y = 3 - 3x3 at the point (2,-21) and write your answer in the form: y = mx + b, where m is the slope and b is the y-intercept. Given Calculate the tangent line at the point (49,56) y = (x -49) +56 f(x) = x+x