If y = f(g(x)) = (fog)x, then d/dx ((f(g(x)) = f'(g(x))g'(x) Proof: Now u = g(x+x) -g(x)
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Question:
If y = f(g(x)) = (fog)x, then d/dx ((f(g(x)) = f'(g(x))g'(x)
Proof: Now u = g(x+x) -g(x)
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