Ignore the equation in the figure below. A process is considered to be a six-sigma process if the (mean + 6 sigma) is no greater than the upper specification limit (USL) and its (mean - 6 sigma) is no less than the lower specification limit (LSL). Is the process shown in the figure below a six-sigma process? (The picture is drawn to scale.) 8 Definitely No, but it would be if it were centered Definitely not. Cannot determine without further information