(ii) greater than 490 L per day X = z score = Probability p (x $ 490) = Probability p (x 2 490) = (ii) between 350 L and 525 L per day X = X = z score = z score = Probability p (x s 350) = Probability p (x $ 525) = Probability p (350 s x s 525) = % B) Determine the per day water usage per person corresponding to the: Mean (J) = Standard Deviation (0) =(i) For 23.25th percentile Probability (p)= 4 decimal places z score = X = The 23.25th percentile amount is (ii) middle 50% of all Canadian residents for middle 50% Probability lies between % to P1= 4 decimal places P2= 4 decimal places Z1= Z2 = X1 = L X2 = For middle 50% of all Canadian uses lies between toCanada is one of the largest per capita users of fresh water in the world. The implementation of water meters on residential homes has made measuring this usage more accurate. Suppose recent estimates suggest water usage in residential homes is normally distributed with a mean of 400 L per person per day and a standard deviation of 65 L per person per day. Mean () = Standard Deviation (0) = A) If a Canadian resident is randomly selected, calculate the probability that their daily water use is: (i) less than 300 L per day X = z score = Probability p (x s 300) = (ii) greater than 490 L per day X : z score = Probability p (x s 490) =