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(ii) Use the two measures of location that you found above to explain which dataset has the higher yield on average. [2] (iii) Use all

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(ii) Use the two measures of location that you found above to explain which dataset has the higher yield on average. [2] (iii) Use all three measures of spread that you found above to explain which dataset shows greater variation. (iv) The boxplot in Figure 1 is for the dataset for variety A. The boxplot is skewed. Is it skewed to the left or to the right? What does this tell you about how the yields are spread for variety A? [2] Variety A 1.3 Mass (ha) (v) Keith produces the histogram in Figure 2 for the dataset for variety B. Explain why the histogram is incorrect for this dataset. [2] Variety B Frequency 0.5 (c) For variety B. Keith draws a scatterplot of the mass of the yield against the number of potatoes. He calculates the correlation coefficient as 0.275. (i) What does the size of the correlation coefficient tell you about the relationship between the mass of the yield and the number of potatoes? [21 (ii) If the correlation coefficient had been 0.978, would that provide proof that the munber of potatoes determines the mass of the yield? Explain your answer. [2] page 3 of 7(b) The masses (in kg) of the yields for twelve plants from each of two varieties are shown in Table 1, correct to two decimal places. Table 1 Keith's potato yields Mass of potato yield in kg Plant Variety A Variety B 1.04 1.27 1.91 1.60 1.69 1.84 1.78 1.08 0.85 0.83 1.46 1.01 0.55 2.02 1.07 1.66 2.35 1.40 10 1.06 1.34 11 1.11 2.19 12 0.74 0.84 (Source: Keith's potato records) (i) Enter the data for the yields of the two varieties into two new lists in Dataplotter. Copy and complete the table below. The mean, rounded to two decimal places, is given for you as a check that you have entered the data correctly. Round answers where necessary to two decimal places. [2] Variety A Variety B Minimum (Min) Median Maximum (Max) Mean 1.30 1.42 Standard deviation (SD) Interquartile range (IQR) Range

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