Question
I'm getting this wrong repeatedly too. Please help. I'm taking 56, the probability that both pedestrian and driver are intoxicated and dividing that with 986=
I'm getting this wrong repeatedly too. Please help.
I'm taking 56, the probability that both pedestrian and driver are intoxicated and dividing that with 986= 0.05679513. Or 5.67. This is wrong.
The table summarizes results from 986 pedestrian deaths that were caused by automobile accidents.
| Driver Intoxicated? | Pedestrian Intoxicated? | |
| Yes | No | |
| Yes | 56 | 79 |
| No | 229 | 622 |
If one of the pedestrian deaths is randomly selected, find the probability that both the pedestrian and the driver were intoxicated. Report the answer as a percent rounded to one decimal place accuracy.
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High School Math 2012 Common-core Algebra 2 Grade 10/11
Authors: Savvas Learning Co
Student Edition
9780133186024, 0133186024
