Imagine a square conductive loop made of thin aluminum wire (shown in black in the figure). The length of one side of this square loop is c = 0.5 m. This loop is partially exposed to an external magnetic field B = - BoZ which points towards the inside of the screen (Bo is a constant). In fact, only the top part of the conductive loop is in the magnetic field. In the figure, the magnetic field exists only in the region shaded in blue. The mass of the ball is m = 0.05 kg and its resistance R = 20 ?. The loop is initially at rest and no current is present. However. when she is released, it begins to fall downwards due to gravity and its speed becomes V. has. Calculate the magnetic flux passing through this loop as a function of y. b. Determine the current I (as a function of v) which will be induced in the conductive loop. Don't forget to include the direction of this current (clockwise or counter-clockwise). vs. The buckle will undergo an upward magnetic force which will oppose the weight of the loop (Fg = mg, where |g| = 9.8 m/s^2). The loop will fall and reach a constant terminal velocity. If B = -BoZ = -2Z Tesla, what is this terminal velocity in m/s?