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Imagine running a disjoint set in reverse, starting with no barns open and iteratively opening them At each point in time, we can see how

Imagine running a disjoint set in reverse, starting with no barns open and
iteratively opening them
At each point in time, we can see how many separate trees are in our
disjoint set.
If the answer is 1, then every open barn is connected, otherwise they are
not.
A relatively slight modification to a regular disjoint set class will answer this
query (download disjoint set with path compression code)
Modify the disjoint set code into stand-alone disjoint class and add Main
class
Add a variable numTrees to Disjoint Set class, initialize the numTrees in the
constructor
Update the numTrees during Union if the Union is successful SolutionI need help finishing this JAVA Code. The rest of the code is correct I just need help with the class dset,public int find(int id),public boolean union(int id1, int id2), and the class pair. import java.util.*;
import java.io.*;
public class Main {
public static int n;
public static int e;
public static ArrayList[] graph;
public static void main(String[] args){
// TODO Auto-generated method stub
Scanner scanner = new Scanner(System.in);
//Read data
n = scanner.nextInt();
e = scanner.nextInt();
graph = new ArrayList[n];
for(int i =0; i();
//Read edges
for(int i =0; i e; i++){
int v1= scanner.nextInt()-1;
int v2= scanner.nextInt()-1;
graph[v1].add(v2);
graph[v2].add(v1);
}
// store items to be removed
int[] remList = new int[n];
for(int i=0; i=0; i--){
int item = remList[i];
for (int j =0; j
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