Question
Implement quadratic probing as a rehash technique. This is the code that I have so far [from a textbook that can be found at http://interactivepython.org/runestone/static/pythonds/SortSearch/Hashing.html#analysis-of-hashing):
Implement quadratic probing as a rehash technique.
This is the code that I have so far [from a textbook that can be found at http://interactivepython.org/runestone/static/pythonds/SortSearch/Hashing.html#analysis-of-hashing):
class HashTable: def __init__(self): self.size = 11 self.slots = [None] * self.size self.data = [None] * self.size
def put(self,key,data): hashvalue = self.hashfunction(key,len(self.slots))
if self.slots[hashvalue] == None: self.slots[hashvalue] = key self.data[hashvalue] = data else: if self.slots[hashvalue] == key: self.data[hashvalue] = data #replace else: nextslot = self.rehash(hashvalue,len(self.slots)) while self.slots[nextslot] != None and \ self.slots[nextslot] != key: nextslot = self.rehash(nextslot,len(self.slots))
if self.slots[nextslot] == None: self.slots[nextslot]=key self.data[nextslot]=data else: self.data[nextslot] = data #replace
def hashfunction(self,key,size): return key%size
def rehash(self,oldhash,size): return (oldhash+1)%size
def get(self,key): startslot = self.hashfunction(key,len(self.slots))
data = None stop = False found = False position = startslot while self.slots[position] != None and \ not found and not stop: if self.slots[position] == key: found = True data = self.data[position] else: position=self.rehash(position,len(self.slots)) if position == startslot: stop = True return data
def __getitem__(self,key): return self.get(key)
def __setitem__(self,key,data): self.put(key,data)
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