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Implement the boolean function f=(a+~b+c)*b using only NOT and 2-input NAND gates By using Demorgan's LAW I can get: f=(~a*~b)+(~c*~b) Just by looking at the
Implement the boolean function f=(a+~b+c)*b using only NOT and 2-input NAND gates
By using Demorgan's LAW I can get: f=(~a*~b)+(~c*~b)
Just by looking at the expresion and drawing out the cirucuit i know that I can simplify it to: f=(a+c)*b
but im not too sure how to do this with boolean algebra, also is f=(a+c)*b the best reduction
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