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import java.util.List; import java.util.LinkedList; import java.util.Queue; / * * * Your implementation of LSD Radix Sort. * / public class Sorting { / * *

import java.util.List;
import java.util.LinkedList;
import java.util.Queue;
/**
* Your implementation of LSD Radix Sort.
*/
public class Sorting {
/**
* Implement LSD (least significant digit) radix sort.
*
* It should be: out-of-place stable not adaptive
*
* Have a worst case running time of: O(kn) And a best case running time of:
* O(kn)
*
* For this question, you are given k: the number of digits in the greatest
* magnitude number in arr. Because of this, you do not need to make an initial
* O(n) pass through to determine this number.
*
* At no point should you find yourself needing a way to exponentiate a number;
* any such method would be non-O(1). Think about how how you can get each power
* of BASE naturally and efficiently as the algorithm progresses through each
* digit.
*
* You may use an ArrayList or LinkedList if you wish. Be sure the List
* implementation you choose allows for stability while being as efficient as
* possible.
*
* Do NOT use anything from the Math class except Math.abs().
*
* You may assume that the passed in array is valid and will not be null.
*
* @param arr The array to be sorted.
* @param k The number of digits in the greatest magnitude number in arr.
*/
public static void lsdRadixSort(int[] arr, int k){
// WRITE YOUR CODE HERE (DO NOT MODIFY METHOD HEADER)!
}
}

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