import numpy as np def menu(): print("MENU") print("__________________________") print("1) Create a 3-by-3 Array") print("2) Display cube Values for elements in array") print("3) Add 7 to every element and display result") print("4) Multiply elements by 6 and display result") print("5) Exit") menu()

choice = int(input("Please select a menu option between 1 and 5: ")) evens = np.array while choice != 0: if choice == 1: evens = np.arange(1,10).reshape(3,3) print(str(evens*2).replace(' [', '').replace('[', '').replace(']', '')) elif choice == 2: cubed = (evens*2) **3 print(str(cubed).replace(' [', '').replace('[', '').replace(']', '')) elif choice == 3: addition = (evens*2) + 7 print(str(addition).replace(' [', '').replace('[', '').replace(']', ''))

elif choice == 4: multiply = (evens*2) * 6 print(str(multiply).replace(' [', '').replace('[', '').replace(']', '')) elif choice == 5: print("Exiting program") break else: print("invalid option") print() menu() choice = int(input("Please select a menu option between 1 and 5: "))

I have this program written so far. It does what I want it to do, but I can not figure out how to have the if statements 2-4 verify if the array was created in choice 1. It runs well if I create the array in choice 1 first then proceed with the options. If I go straight to option 2 it gives me an error. I need the program to verify if the array in option 1 was created first and if not state that the array has not been created and then pull the menu open once again to make another choice. This is in python