: In $0-$sum RPS game $($below$)$ mixed strategy of player one is $[1/3$ : R; $1/3$ :

P; $1/3$ : S$],$ strategy of player $2$ is $[1/2$ : R; $1/4$ : P; $1/4$ : S$].$ Is there expected to be a winner in

this game? Show your calculations