In 1999, the average percentage of women who received prenatal care per country was 80.1%. The table below contains the percentage of woman receiving prenatal care in 2009 for a random sample of countries. Do the data show that the average percentage of women receiving prenatal care in 2009 was higher than in 1999? Test at the 8% level.

percentage of women receiving prenatal care in percent

93

88.4

99.1

97.3

97.95

91.8

97.95

91.8

93.68

99.1

92.47

93.63

95

99.1

99.1

100

92.2

98.2

100

94.3

99.1

100

92.47

95.8

92.41

99.1

93.2

100

99.1

100

P: Parameter

What is the correct parameter symbol for this problem? ? X p X n N s p What is the wording of the parameter in the context of this problem? Select an answer The mean percentage of women receiving prenatal care of all countries A randomly selected country The percentage of women receiving prenatal care of a randomly selected country All countries 30 randomly selected countries The mean percentage of women receiving prenatal care in 30 randomly selected countries H: Hypotheses

Fill in the correct null and alternative hypotheses:

H0:H0: ? X p p N n s X ? < = > 80.1 percent HA:HA: ? N s p X X n p ? < > = 80.1 percent

A: Assumptions

Since Select an answer qualitative quantitative information was collected from each object, what conditions do we need to check?

Check all that apply.

• is known
• no outliers in the data
• N20nN20n
• n30n30 or normal population
• n(1p)10n(1-p)10
• outliers in the data
• np10np10
• n(1p)10n(1-p)10
• n(p)10n(p)10
• is unknown

Check those assumptions: 1. Is the value of known? ? no yes

2. Which of the following is the correct modified boxplot?

888990919293949596979899100percentage of women receiving prenatal care in percent88.49397.62599.1100[Graphs generated by this script: setBorder(15); initPicture(88,100,-3,6);axes(1,100,1,null,null,1,'off');text([93.8,-3],"percentage of women receiving prenatal care in percent");line([88.4,2],[88.4,4]); rect([93,2],[99.1,4]); line([97.625,2],[97.625,4]);line([100,2],[100,4]); line([88.4,3],[93,3]); line([99.1,3],[100,3]);fontsize*=.8;fontfill='blue';text([88.4,4],'88.4','above');text([93,4],'93','above');text([97.625,4],'97.625','above');text([99.1,4],'99.1','above');text([100,4],'100','above');fontfill='black';fontsize*=1.25;] 888990919293949596979899100percentage of women receiving prenatal care in percent88.49395.312599.1100[Graphs generated by this script: setBorder(15); initPicture(88,100,-3,6);axes(1,100,1,null,null,1,'off');text([93.8,-3],"percentage of women receiving prenatal care in percent");line([88.4,2],[88.4,4]); rect([93,2],[99.1,4]); line([95.3125,2],[95.3125,4]);line([100,2],[100,4]); line([88.4,3],[93,3]); line([99.1,3],[100,3]);fontsize*=.8;fontfill='blue';text([88.4,4],'88.4','above');text([93,4],'93','above');text([95.3125,4],'95.3125','above');text([99.1,4],'99.1','above');text([100,4],'100','above');fontfill='black';fontsize*=1.25;] 888990919293949596979899100percentage of women receiving prenatal care in percent88.49397.62599.55100[Graphs generated by this script: setBorder(15); initPicture(88,100,-3,6);axes(1,100,1,null,null,1,'off');text([93.8,-3],"percentage of women receiving prenatal care in percent");line([88.4,2],[88.4,4]); rect([93,2],[99.55,4]); line([97.625,2],[97.625,4]);line([100,2],[100,4]); line([88.4,3],[93,3]); line([99.55,3],[100,3]);fontsize*=.8;fontfill='blue';text([88.4,4],'88.4','above');text([93,4],'93','above');text([97.625,4],'97.625','above');text([99.55,4],'99.55','above');text([100,4],'100','above');fontfill='black';fontsize*=1.25;] 888990919293949596979899100percentage of women receiving prenatal care in percent88.490.797.62599.1100[Graphs generated by this script: setBorder(15); initPicture(88,100,-3,6);axes(1,100,1,null,null,1,'off');text([93.8,-3],"percentage of women receiving prenatal care in percent");line([88.4,2],[88.4,4]); rect([90.7,2],[99.1,4]); line([97.625,2],[97.625,4]);line([100,2],[100,4]); line([88.4,3],[90.7,3]); line([99.1,3],[100,3]);fontsize*=.8;fontfill='blue';text([88.4,4],'88.4','above');text([90.7,4],'90.7','above');text([97.625,4],'97.625','above');text([99.1,4],'99.1','above');text([100,4],'100','above');fontfill='black';fontsize*=1.25;]

Are there any outliers? Select an answer Yes, the normal probability plot shows outliers. Yes, the modified boxplot shows outliers. No, the histogram shows no outliers. No, the normal probability plot shows no outliers. No, the modified boxplot shows no outliers. Yes, the histogram shows outliers.

3. nn = 30 which is ? < 30 Is it reasonable to assume the population is normally distributed? Select an answer Not necessary to check since the sample size is at least 30. Not necessary to check since the sample size is less than 30. Yes since the normal probability plot is roughly linear with no outliers. Yes since the normal probability plot is roughly bell-shaped with no outliers. No, since the normal probability plot is not roughly linear. No, since the normal probability plot is not roughly bell-shaped. N: Name the test

The conditions are met to use a Select an answer Paired T-Test 1-Proportion Z-Test 2-Sample T-Test T-Test 2-Proportion Z-Test . T: Test Statistic

The symbol and value of the random variable on this problem are as follows: ? p X p X s n N = 96.1753 percent

The test statistic formula set up with numbers is as follows:

Round values to 3 decimal places. t=Xsn=t=X-sn= ((((96.1753 - 80.1 )) // 3.412 // 30 ))))

The final answer for the test statistic from technology is as follows:

Round to 2 decimal places.

t = O: Obtain the P-value

Report the final answer to 4 decimal places.

It is possible when rounded that a p-value is 0.0000 P-value = .0000 M: Make a decision

Since the p-value ? < = > , we Select an answer fail to reject H reject H fail to reject H accept H reject H . S: State a conclustion

There Select an answer is is not significant evidence to conclude

so i have attempted this question severally but i keep getting wrong.