In a 250.0 mL beaker, 10.0 mL 0.200 M H3PO4, 20.0 mL 0.400 M Na3P04, 10.0 mL of 0.200 M NaOH and 70.0 mL of 0.300 M HCl are added. Answers After mixing, the total volume was made up to 200.0 mL. For Mg(OH)2 in this mixture Calculate the molar resolution. Mg(OH)2 Kce= 7,1 x 10-12 H3PO4 Kai = 7,11 x 103 K2 = 6, 32 x 108 K 3 = 4,5 x 10-13