In a Bureau of Labor Statistics study, 500 students who graduated in May were surveyed to determine how many were unable to find a job in their area of study by the following October. In 2013, 3.8% indicated that they could not find a job while, in 2014, the percentage was 3.1%. Construct a 95% confidence interval for the difference between these two years. Interpret this confidence interval. N=500 P1=.038 P2=.031 038-.031+-z.025 sq.root .038x.962/500 = .031x.969/500 095 X=.05 x/2=.025 1.96 007+-1.96 sq. root .00607+.00006 007+-.022 -.015