In a clinical trial of a drug intended to help people stopsmoking, 128 subjects were treated with the drug for 13 weeks, and 16 subjects experienced abdominal pain. If someone claims that more than 8% of thedrug's users experience abdominalpain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value ofp, the power of the test is 0.95. Interpret this value of the power of the test.

The power of 0.95 shows that there is a

nothing

% chance of rejecting the

alternative

hypothesis of p=

nothing

when the true proportion is actually

nothing

. Thatis, if the proportion of users who experience abdominal pain is actually

nothing

, then there is a

nothing

% chance of supporting the claim that the proportion of users who experience abdominal pain is

greater

less

than 0.08.

(Type integers or decimals. Do notround.)