In a Leichtman Research Group survey of 1050 TV households, 75.3% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the that the percentage of all homes with at least one Internet-connected TV device is equal to 82%. Test that claim using a 0.05 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Ho: P V Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses. H1 : P V (Type integers or decimals. Do not round.) Identify the test statistic. z= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 82%. O Help me solve this View an example Get more help - DELL a : graduate application Go gc: graduate candidacy Go grpet: student petitions Go grcomm: committee approval Go ms: master summary cors: registration summary Go he: historicudent unofficial transcript rses (will list credit number for courses with no go testl: test scores Go to: Internation .may have multiple to previous or next gerformation) creen. Directions are at the bottom or chef 11 to moon you and and fast" To look up class so to 2 then I waitlist F9 wLSec waitlist by student F9 WL