Question
In a random sample of 40 refrigerators, the mean repair cost was $133.00 and the population standard deviation is $17.20. A 95% confidence interval for
In a random sample of 40 refrigerators, the mean repair cost was $133.00 and the population standard deviation is $17.20. A 95% confidence interval for the population mean repair cost is left parenthesis 127.67 comma 138.33 right parenthesis.
Change the sample size to n=80. Construct a 95% confidence interval for the population mean repair cost. Which confidence interval is wider? Explain. Construct a 95% confidence interval for the population mean repair cost.
The 95% confidence interval is ( _____, _____ ). (Round to two decimal places as needed.)
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