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In a random sample of 60 refrigerators, the mean repair cost was $135.00 and the population standard deviation is $19.10. Construct a 90%confidence interval for

In a random sample of 60 refrigerators, the mean repair cost was $135.00 and the population standard deviation is $19.10. Construct a 90%confidence interval for the population mean repair cost. Interpret the results.

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