Question
In a random sample of sixsix microwave ovens, the mean repair cost was $65.0065.00 and the standard deviation was $11.0011.00. Assume the population is normally
In a random sample of sixsix microwave ovens, the mean repair cost was $65.0065.00
and the standard deviation was $11.0011.00. Assume the population is normally distributed and use a t-distribution to construct a 9090% confidence interval for the population mean mu. What is the margin of error of mu Interpret the results.The 9090% confidence interval for the population mean is
(nothing ,nothing ).(Round to two decimal places as needed.)The margin of error is nothing .
(Round to two decimal places as needed.)
Interpret the results. Choose the correct answer below.
A.
It can be said that
9090%
of microwaves have a repair cost between the bounds of the confidence interval.
B.
With
9090%
confidence, it can be said that the population mean repair cost is between the bounds of the confidence interval.
C.
If a large sample of microwaves are taken approximately
9090%
of them will have repair costs between the bounds of the confidence interval.
D.
With
9090%
confidence, it can be said that the repair cost is between the bounds of the confidence interval.
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