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Exercise-10= A pipe 10 cm in diameter contains steam at 200C. It is covered with an insulating material that is-5-cm-thick. This insulating material has a constant of thermal- conductivity K = 0.00060-cal/cm sec. The outside surface of the system is 35-C. Find the heat loss per hour from a 2-meter length of the pipe. 35 01 200 X1 5 cmi Q=KA(didx -Ko(2 x)dt/dr QuS"dr/r=-K.2nLIST dT1 Q (2 K.LT-T.))/In(m/ri)1 L=200cm T: 200degC L.=35degC 12=0.1m n=0.05m-1 + Ko=0.00060 cal/cm2sec Q 2x*0.00060*200*(200-35)In(10/5) Q=179.48cal/sec * 60sec/1min * 60min/1 br= 646128 cakbr.]