In a study, temperature readings were taken at different locations in 1990 and in 2011. The average daily temperatures for the month of June in each of 36 different locations are listed below. We would like to see if there is any difference between the mean temperatures of 1990 and 2011. If you believe the populations are independent, then assume the population variances are equal. Location Average Standard deviation 1990 36 83 13.0 2011 36 87 9.2 Difference (d = y1990 - y2011) 36 -4.0 5.0 Perform a statistical test. (a) What are the null and alternative hypotheses? Ho: P <: ha: p what is the test statistic your answer to decimal places if needed. using statistical table p-value based on reject null hypothesis at significance level of this data provides sufficient evidence conclude that mean temperature in less than>