In a survery of 386 households, a Food Marketing Institute found that 239 households spend more than $125 a week on groceries. Please find the 99.9% confidence interval for the true proportion of the households that spend more than $125 a week on groceries.

A. Enter your answer as anopen-interval(i.e., parentheses) using decimals (not percents) accurate to three decimal places.

Confidence interval =BLANK

B. Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

BLANK <p< BLANK

C. Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.

p= BLANK BLANK