In a system consisting of four processes and five resource types, the current allocation and maximum needs are as follows: Process PO P1 P2 P3 Allocation 10211 20110 11010 Maximum 11213 22210 21310 11221 Available 00x12 What is the smallest value of 'x' that can keep the system in a safe state? Once you find the 'x value, find a safe execution order using the Safety Algorithm we discussed in the lecture. Include a step-by-step walk-through of the Safety Algorithm