In an asenkron transmission a character size is 5 bits. When 2000 characters are transmitted, if total overhead amount is 8 kbit, which answer is correct? O a. Stop Bit = 1,5 Parity = "No" Total Data Size = 14,25 Kbit O b. Stop Bit = 1,5 Parity = "Even" Total Data Size = 14,45 Kbit O c. Stop Bit = 1,5 Parity = "Even" Total Data Size = 20,40 Kbit O d. Stop Bit = 1,5 Parity = "Odd" Total Data Size = 17,85 Kbit O e. Stop Bit = 2 Parity = "Odd" Total Data Size = 18,00 Kbit