In an asenkron transmission a character size is 6 bits. In this transmission, if total overhead amount is 6 Kbit and total data size is 18 Kbit, which answer is correct? O a. Stop Bit = 1 Parity = "Odd" Amount of transmitted characters = 2000 O b. Stop Bit = 1,5 Parity = "Even" Amount of transmitted characters = 2400 O c. Stop Bit = 1,5 Parity = "Even" Amount of transmitted characters = 1700 Od. Stop Bit = 1,5 Parity = "No" Amount of transmitted characters = 1900 O e Stop Bit = 1 Parity = "Odd" Amount of transmitted characters = 2100