In answering below questions, assume the sizes of tvpes are as mentioned here: char l byte, short $2$ bytes, int $4$ bytes,

unsigned int $4$ bytes, loat $4$ bytes, long $8$ bytes, double & bytes, and $8$ bytes for a pointer. You must mention the function

prototype when defning any function.

Write the output fromn the below code:

int main $($void$)$ f

double z $[3][4]=\{\{1,4,7,10\},(2,5,8,11\},\{3,6,9,12\}\}$i

void $*$zaddr $=($void$*)$ &z;

return $0$: $\}$

printf $("$a: $\%$ld$,\%1$d$,\%$ld $\backslash$a$",(($void$*)$ &z $[1]-$zaddr$),(($void$*)$ &z $[0)[1]-$zaddr$))$;

printf $("$b: $\%1$d$,\%$ld$,\%$ld

$",(($void$*)($&z $[0]+1)-$zaddr $),$

$(2)(3$ points$)$

$(3)(3$ points$)$

Assuming the address of the first byte of z is Ox$754$c$0,$ fll in the guestion marks and list the output:

int main $($vo id$)$

Write the output from the below code:

$1$I you nnd uny

$(($void$*)$ z $[1]-$zaddr$),$

double z $[3][4]=\{\{1,4,7,10\},(2,5,8,11),(3,6,9,12)\}$;

printf $("$a: $\%?,\%?$

$",**$z $[0]+(2*$sizeof $($z $[0])),$ &z $[2][0]+(1*$sizeof $($z $[2][0])))$;

printf $("$c: $\%?,\%?,\%?$

$",*($z $+2),*(*($z$+2)+1),*($z $+2)+2)$;

int main $($void$)$

double d $[3]=(57,89,102\}$;

double $*$p $[3]=\{$&d$[1],$ &d$[1],$ printf $("$a: $\%1$f$,\%1$f$,\%1$f

$",$

printf $("$b: $\%1$f$,\%1$f$,\%1$f

$",$

return $0$: $\}$

$1$

&d$[1]\}$:

R$.$ Inkulu

$*$p$[1]++,*--$p $[2],*($p $[$o$]++))$;

$*$p $[0],*$p$[1$J$,*$p $[2])$;

Roll Number:

$(($void $*)($z$+1)-$zaddr$),(($void $*)($&z$+1)-$zaddr$))$;