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In C++ Part - 1: Implement a singly linked list ADT to store a collection of doubles. PLEASE USE THE LINKS PROVIDED BELOW (You are

In C++

Part - 1: Implement a singly linked list ADT to store a collection of doubles.

PLEASE USE THE LINKS PROVIDED BELOW

(You are allowed to extend the demo code posted on GitHub for this homework. link: https://github.com/Premdeep/CSC340-Summer-2017/tree/master/LinkedList ).

Make sure to provide an interactive user interface to test these new functions in the main() for grader . Your ADT will include the following member functions:

--- a default constructor

--- the "big-3": destructor, copy constructor and overloaded assignment operator

1. a member function pushFront(data) that inserts a node with data at the front of the list

2. a member function pushBack(data) that appends a node with data at the back of the list

3. a member function popFront() that removes first node of the list.

4. a member function popBack() that removes last node of the list.

5. a member function insert(index, val) that inserts a new node with value "val" at a specific position mentioned by the index argument.

6. a member function deleteDuplicates(val) that deletes a node with that number and all its copies from the list, where these copies can be located anywhere in the list.

7. a member function mtoLastElement(M) that returns Mth to the last element of a list such that when M = 0, the last element of the list is returned.

8. a member function size() that returns the size of the list.

9. an overloaded put operator (<<) to print out all the data items stored in a linked list. Note that you are recommended to overload this operator as a friend function of the LinkedList class.

10. a member function reverseList() that reverses a linked list without recreating a temporary copy of this linked list. In other words, your function CAN NOT use the 'new' operator. Here is an example, if a list contains the following data items, 3 -> 5 -> 1 -> 7; this reverse() function will change the list to 7 -> 1 -> 5 -> 3.

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