Question
In Einstein's theory of relativity, we can derive that E(v)=(mc^2)/(sqrt(1-(v^2/c^2))) whereE(v)is the energy of an object with Rest massmand velocityv. Let us analyze this more
In Einstein's theory of relativity, we can derive that
E(v)=(mc^2)/(sqrt(1-(v^2/c^2)))
whereE(v)is the energy of an object with "Rest mass"mand velocityv.
Let us analyze this more closely.
First find the linear approximation to the functionf(u)=(mc^2)/(sqrt(1-u)) at u=0.
Using this approximation, and substitutingu=v^2/c^2, we can obtain an approximation for E(v)which is valid for small velocitiesv.
The approximation you obtain should have two terms. One of which is the famousE=mc^2(representing the resting energy) and the other should be the classical kinetic energy of the object.
The local linearization of(mc^2)/(sqrt(1-u)) at u=0 is ?
So we get that E(v)
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