In figure below, the work done by the electric force as the test charge (qo = +6.5 x 10-5 C) moves from A to B is WAB = +7.6 x 10-4 J. (a) Find the value of the difference, A(EPE) = EPEg-EPEA, in the electric potential energies of the charge between these points. (b) Determine the potential difference, AV = VB - VA, between the points. + + + ++ +++++++++ A 90 F = q0E B VF = q0E