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In Java programming, class Overload { void ovlDemo ( ) { System.out.println ( No parameters ) ; } / / Overload ovlDemo for one
In Java programming,
class Overload
void ovlDemo
System.out.printlnNo parameters";
Overload ovlDemo for one integer parameter.
void ovlDemoint a
System.out.printlnOne parameter: a;
Overload ovlDemo for two integer parameters.
int ovlDemoint a int b
System.out.printlnTwo parameters: a b;
return a b;
Overload ovlDemo for two double parameters.
double ovlDemodouble a double b
System.out.printlnTwo double parameters: a b;
return a b;
class OverloadDemo
public static void mainString args
Overload ob new Overload;
int resI;
double resD;
call all versions of ovlDemo
obovlDemo;
System.out.println;
obovlDemo;
System.out.println;
resI obovlDemo;
System.out.printlnResult of obovlDemo: resI;
resD obovlDemo;
System.out.printlnResult of obovlDemo: resD;
A How does void ovlDemo and int ovlDemo impact the output of the program?
B What will the program output when the method is overloaded with the same type and numbers of parameters?
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